\(\int \frac {(a+b x^3)^{8/3}}{(c+d x^3)^3} \, dx\) [111]

Optimal result

Integrand size = 21, antiderivative size = 391 \[ \int \frac {\left (a+b x^3\right )^{8/3}}{\left (c+d x^3\right )^3} \, dx=-\frac {(b c-a d) x \left (a+b x^3\right )^{5/3}}{6 c d \left (c+d x^3\right )^2}-\frac {(b c-a d) (6 b c+5 a d) x \left (a+b x^3\right )^{2/3}}{18 c^2 d^2 \left (c+d x^3\right )}+\frac {b^{8/3} \arctan \left (\frac {1+\frac {2 \sqrt [3]{b} x}{\sqrt [3]{a+b x^3}}}{\sqrt {3}}\right )}{\sqrt {3} d^3}-\frac {(b c-a d)^{2/3} \left (9 b^2 c^2+6 a b c d+5 a^2 d^2\right ) \arctan \left (\frac {1+\frac {2 \sqrt [3]{b c-a d} x}{\sqrt [3]{c} \sqrt [3]{a+b x^3}}}{\sqrt {3}}\right )}{9 \sqrt {3} c^{8/3} d^3}-\frac {(b c-a d)^{2/3} \left (9 b^2 c^2+6 a b c d+5 a^2 d^2\right ) \log \left (c+d x^3\right )}{54 c^{8/3} d^3}+\frac {(b c-a d)^{2/3} \left (9 b^2 c^2+6 a b c d+5 a^2 d^2\right ) \log \left (\frac {\sqrt [3]{b c-a d} x}{\sqrt [3]{c}}-\sqrt [3]{a+b x^3}\right )}{18 c^{8/3} d^3}-\frac {b^{8/3} \log \left (-\sqrt [3]{b} x+\sqrt [3]{a+b x^3}\right )}{2 d^3} \]

[Out]

-1/6*(-a*d+b*c)*x*(b*x^3+a)^(5/3)/c/d/(d*x^3+c)^2-1/18*(-a*d+b*c)*(5*a*d+6*b*c)*x*(b*x^3+a)^(2/3)/c^2/d^2/(d*x
^3+c)-1/54*(-a*d+b*c)^(2/3)*(5*a^2*d^2+6*a*b*c*d+9*b^2*c^2)*ln(d*x^3+c)/c^(8/3)/d^3+1/18*(-a*d+b*c)^(2/3)*(5*a
^2*d^2+6*a*b*c*d+9*b^2*c^2)*ln((-a*d+b*c)^(1/3)*x/c^(1/3)-(b*x^3+a)^(1/3))/c^(8/3)/d^3-1/2*b^(8/3)*ln(-b^(1/3)
*x+(b*x^3+a)^(1/3))/d^3+1/3*b^(8/3)*arctan(1/3*(1+2*b^(1/3)*x/(b*x^3+a)^(1/3))*3^(1/2))/d^3*3^(1/2)-1/27*(-a*d
+b*c)^(2/3)*(5*a^2*d^2+6*a*b*c*d+9*b^2*c^2)*arctan(1/3*(1+2*(-a*d+b*c)^(1/3)*x/c^(1/3)/(b*x^3+a)^(1/3))*3^(1/2
))/c^(8/3)/d^3*3^(1/2)

Rubi [A] (verified)

Time = 0.30 (sec) , antiderivative size = 391, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.238, Rules used = {424, 540, 544, 245, 384} \[ \int \frac {\left (a+b x^3\right )^{8/3}}{\left (c+d x^3\right )^3} \, dx=-\frac {(b c-a d)^{2/3} \left (5 a^2 d^2+6 a b c d+9 b^2 c^2\right ) \arctan \left (\frac {\frac {2 x \sqrt [3]{b c-a d}}{\sqrt [3]{c} \sqrt [3]{a+b x^3}}+1}{\sqrt {3}}\right )}{9 \sqrt {3} c^{8/3} d^3}-\frac {(b c-a d)^{2/3} \left (5 a^2 d^2+6 a b c d+9 b^2 c^2\right ) \log \left (c+d x^3\right )}{54 c^{8/3} d^3}+\frac {(b c-a d)^{2/3} \left (5 a^2 d^2+6 a b c d+9 b^2 c^2\right ) \log \left (\frac {x \sqrt [3]{b c-a d}}{\sqrt [3]{c}}-\sqrt [3]{a+b x^3}\right )}{18 c^{8/3} d^3}+\frac {b^{8/3} \arctan \left (\frac {\frac {2 \sqrt [3]{b} x}{\sqrt [3]{a+b x^3}}+1}{\sqrt {3}}\right )}{\sqrt {3} d^3}-\frac {b^{8/3} \log \left (\sqrt [3]{a+b x^3}-\sqrt [3]{b} x\right )}{2 d^3}-\frac {x \left (a+b x^3\right )^{2/3} (b c-a d) (5 a d+6 b c)}{18 c^2 d^2 \left (c+d x^3\right )}-\frac {x \left (a+b x^3\right )^{5/3} (b c-a d)}{6 c d \left (c+d x^3\right )^2} \]

[In]

Int[(a + b*x^3)^(8/3)/(c + d*x^3)^3,x]

[Out]

-1/6*((b*c - a*d)*x*(a + b*x^3)^(5/3))/(c*d*(c + d*x^3)^2) - ((b*c - a*d)*(6*b*c + 5*a*d)*x*(a + b*x^3)^(2/3))
/(18*c^2*d^2*(c + d*x^3)) + (b^(8/3)*ArcTan[(1 + (2*b^(1/3)*x)/(a + b*x^3)^(1/3))/Sqrt[3]])/(Sqrt[3]*d^3) - ((
b*c - a*d)^(2/3)*(9*b^2*c^2 + 6*a*b*c*d + 5*a^2*d^2)*ArcTan[(1 + (2*(b*c - a*d)^(1/3)*x)/(c^(1/3)*(a + b*x^3)^
(1/3)))/Sqrt[3]])/(9*Sqrt[3]*c^(8/3)*d^3) - ((b*c - a*d)^(2/3)*(9*b^2*c^2 + 6*a*b*c*d + 5*a^2*d^2)*Log[c + d*x
^3])/(54*c^(8/3)*d^3) + ((b*c - a*d)^(2/3)*(9*b^2*c^2 + 6*a*b*c*d + 5*a^2*d^2)*Log[((b*c - a*d)^(1/3)*x)/c^(1/
3) - (a + b*x^3)^(1/3)])/(18*c^(8/3)*d^3) - (b^(8/3)*Log[-(b^(1/3)*x) + (a + b*x^3)^(1/3)])/(2*d^3)

Rule 245

Int[((a_) + (b_.)*(x_)^3)^(-1/3), x_Symbol] :> Simp[ArcTan[(1 + 2*Rt[b, 3]*(x/(a + b*x^3)^(1/3)))/Sqrt[3]]/(Sq
rt[3]*Rt[b, 3]), x] - Simp[Log[(a + b*x^3)^(1/3) - Rt[b, 3]*x]/(2*Rt[b, 3]), x] /; FreeQ[{a, b}, x]

Rule 384

Int[1/(((a_) + (b_.)*(x_)^3)^(1/3)*((c_) + (d_.)*(x_)^3)), x_Symbol] :> With[{q = Rt[(b*c - a*d)/c, 3]}, Simp[
ArcTan[(1 + (2*q*x)/(a + b*x^3)^(1/3))/Sqrt[3]]/(Sqrt[3]*c*q), x] + (-Simp[Log[q*x - (a + b*x^3)^(1/3)]/(2*c*q
), x] + Simp[Log[c + d*x^3]/(6*c*q), x])] /; FreeQ[{a, b, c, d}, x] && NeQ[b*c - a*d, 0]

Rule 424

Int[((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_))^(q_), x_Symbol] :> Simp[(a*d - c*b)*x*(a + b*x^n)^(
p + 1)*((c + d*x^n)^(q - 1)/(a*b*n*(p + 1))), x] - Dist[1/(a*b*n*(p + 1)), Int[(a + b*x^n)^(p + 1)*(c + d*x^n)
^(q - 2)*Simp[c*(a*d - c*b*(n*(p + 1) + 1)) + d*(a*d*(n*(q - 1) + 1) - b*c*(n*(p + q) + 1))*x^n, x], x], x] /;
FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && LtQ[p, -1] && GtQ[q, 1] && IntBinomialQ[a, b, c, d, n, p, q
, x]

Rule 540

Int[((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_))^(q_.)*((e_) + (f_.)*(x_)^(n_)), x_Symbol] :> Simp[(
-(b*e - a*f))*x*(a + b*x^n)^(p + 1)*((c + d*x^n)^q/(a*b*n*(p + 1))), x] + Dist[1/(a*b*n*(p + 1)), Int[(a + b*x
^n)^(p + 1)*(c + d*x^n)^(q - 1)*Simp[c*(b*e*n*(p + 1) + b*e - a*f) + d*(b*e*n*(p + 1) + (b*e - a*f)*(n*q + 1))
*x^n, x], x], x] /; FreeQ[{a, b, c, d, e, f, n}, x] && LtQ[p, -1] && GtQ[q, 0]

Rule 544

Int[(((a_) + (b_.)*(x_)^(n_))^(p_)*((e_) + (f_.)*(x_)^(n_)))/((c_) + (d_.)*(x_)^(n_)), x_Symbol] :> Dist[f/d,
Int[(a + b*x^n)^p, x], x] + Dist[(d*e - c*f)/d, Int[(a + b*x^n)^p/(c + d*x^n), x], x] /; FreeQ[{a, b, c, d, e,
f, p, n}, x]

Rubi steps \begin{align*} \text {integral}& = -\frac {(b c-a d) x \left (a+b x^3\right )^{5/3}}{6 c d \left (c+d x^3\right )^2}+\frac {\int \frac {\left (a+b x^3\right )^{2/3} \left (a (b c+5 a d)+6 b^2 c x^3\right )}{\left (c+d x^3\right )^2} \, dx}{6 c d} \\ & = -\frac {(b c-a d) x \left (a+b x^3\right )^{5/3}}{6 c d \left (c+d x^3\right )^2}-\frac {(b c-a d) (6 b c+5 a d) x \left (a+b x^3\right )^{2/3}}{18 c^2 d^2 \left (c+d x^3\right )}-\frac {\int \frac {-2 a \left (3 b^2 c^2+a d (b c+5 a d)\right )-18 b^3 c^2 x^3}{\sqrt [3]{a+b x^3} \left (c+d x^3\right )} \, dx}{18 c^2 d^2} \\ & = -\frac {(b c-a d) x \left (a+b x^3\right )^{5/3}}{6 c d \left (c+d x^3\right )^2}-\frac {(b c-a d) (6 b c+5 a d) x \left (a+b x^3\right )^{2/3}}{18 c^2 d^2 \left (c+d x^3\right )}+\frac {b^3 \int \frac {1}{\sqrt [3]{a+b x^3}} \, dx}{d^3}-\frac {\left ((b c-a d) \left (9 b^2 c^2+6 a b c d+5 a^2 d^2\right )\right ) \int \frac {1}{\sqrt [3]{a+b x^3} \left (c+d x^3\right )} \, dx}{9 c^2 d^3} \\ & = -\frac {(b c-a d) x \left (a+b x^3\right )^{5/3}}{6 c d \left (c+d x^3\right )^2}-\frac {(b c-a d) (6 b c+5 a d) x \left (a+b x^3\right )^{2/3}}{18 c^2 d^2 \left (c+d x^3\right )}+\frac {b^{8/3} \tan ^{-1}\left (\frac {1+\frac {2 \sqrt [3]{b} x}{\sqrt [3]{a+b x^3}}}{\sqrt {3}}\right )}{\sqrt {3} d^3}-\frac {(b c-a d)^{2/3} \left (9 b^2 c^2+6 a b c d+5 a^2 d^2\right ) \tan ^{-1}\left (\frac {1+\frac {2 \sqrt [3]{b c-a d} x}{\sqrt [3]{c} \sqrt [3]{a+b x^3}}}{\sqrt {3}}\right )}{9 \sqrt {3} c^{8/3} d^3}-\frac {(b c-a d)^{2/3} \left (9 b^2 c^2+6 a b c d+5 a^2 d^2\right ) \log \left (c+d x^3\right )}{54 c^{8/3} d^3}+\frac {(b c-a d)^{2/3} \left (9 b^2 c^2+6 a b c d+5 a^2 d^2\right ) \log \left (\frac {\sqrt [3]{b c-a d} x}{\sqrt [3]{c}}-\sqrt [3]{a+b x^3}\right )}{18 c^{8/3} d^3}-\frac {b^{8/3} \log \left (-\sqrt [3]{b} x+\sqrt [3]{a+b x^3}\right )}{2 d^3} \\ \end{align*}

Mathematica [C] (warning: unable to verify)

Result contains higher order function than in optimal. Order 6 vs. order 3 in optimal.

Time = 11.00 (sec) , antiderivative size = 651, normalized size of antiderivative = 1.66 \[ \int \frac {\left (a+b x^3\right )^{8/3}}{\left (c+d x^3\right )^3} \, dx=\frac {\frac {6 c^{2/3} (-b c+a d) x \left (a+b x^3\right )^{2/3} \left (3 b c \left (2 c+3 d x^3\right )+a d \left (8 c+5 d x^3\right )\right )}{d^2 \left (c+d x^3\right )^2}+\frac {27 b^3 c^{5/3} x^4 \sqrt [3]{1+\frac {b x^3}{a}} \operatorname {AppellF1}\left (\frac {4}{3},\frac {1}{3},1,\frac {7}{3},-\frac {b x^3}{a},-\frac {d x^3}{c}\right )}{d^2 \sqrt [3]{a+b x^3}}+\frac {10 a^3 \left (2 \sqrt {3} \arctan \left (\frac {1+\frac {2 \sqrt [3]{b c-a d} x}{\sqrt [3]{c} \sqrt [3]{b+a x^3}}}{\sqrt {3}}\right )-2 \log \left (\sqrt [3]{c}-\frac {\sqrt [3]{b c-a d} x}{\sqrt [3]{b+a x^3}}\right )+\log \left (c^{2/3}+\frac {(b c-a d)^{2/3} x^2}{\left (b+a x^3\right )^{2/3}}+\frac {\sqrt [3]{c} \sqrt [3]{b c-a d} x}{\sqrt [3]{b+a x^3}}\right )\right )}{\sqrt [3]{b c-a d}}+\frac {6 a b^2 c^2 \left (2 \sqrt {3} \arctan \left (\frac {1+\frac {2 \sqrt [3]{b c-a d} x}{\sqrt [3]{c} \sqrt [3]{b+a x^3}}}{\sqrt {3}}\right )-2 \log \left (\sqrt [3]{c}-\frac {\sqrt [3]{b c-a d} x}{\sqrt [3]{b+a x^3}}\right )+\log \left (c^{2/3}+\frac {(b c-a d)^{2/3} x^2}{\left (b+a x^3\right )^{2/3}}+\frac {\sqrt [3]{c} \sqrt [3]{b c-a d} x}{\sqrt [3]{b+a x^3}}\right )\right )}{d^2 \sqrt [3]{b c-a d}}+\frac {2 a^2 b c \left (2 \sqrt {3} \arctan \left (\frac {1+\frac {2 \sqrt [3]{b c-a d} x}{\sqrt [3]{c} \sqrt [3]{b+a x^3}}}{\sqrt {3}}\right )-2 \log \left (\sqrt [3]{c}-\frac {\sqrt [3]{b c-a d} x}{\sqrt [3]{b+a x^3}}\right )+\log \left (c^{2/3}+\frac {(b c-a d)^{2/3} x^2}{\left (b+a x^3\right )^{2/3}}+\frac {\sqrt [3]{c} \sqrt [3]{b c-a d} x}{\sqrt [3]{b+a x^3}}\right )\right )}{d \sqrt [3]{b c-a d}}}{108 c^{8/3}} \]

[In]

Integrate[(a + b*x^3)^(8/3)/(c + d*x^3)^3,x]

[Out]

((6*c^(2/3)*(-(b*c) + a*d)*x*(a + b*x^3)^(2/3)*(3*b*c*(2*c + 3*d*x^3) + a*d*(8*c + 5*d*x^3)))/(d^2*(c + d*x^3)
^2) + (27*b^3*c^(5/3)*x^4*(1 + (b*x^3)/a)^(1/3)*AppellF1[4/3, 1/3, 1, 7/3, -((b*x^3)/a), -((d*x^3)/c)])/(d^2*(
a + b*x^3)^(1/3)) + (10*a^3*(2*Sqrt[3]*ArcTan[(1 + (2*(b*c - a*d)^(1/3)*x)/(c^(1/3)*(b + a*x^3)^(1/3)))/Sqrt[3
]] - 2*Log[c^(1/3) - ((b*c - a*d)^(1/3)*x)/(b + a*x^3)^(1/3)] + Log[c^(2/3) + ((b*c - a*d)^(2/3)*x^2)/(b + a*x
^3)^(2/3) + (c^(1/3)*(b*c - a*d)^(1/3)*x)/(b + a*x^3)^(1/3)]))/(b*c - a*d)^(1/3) + (6*a*b^2*c^2*(2*Sqrt[3]*Arc
Tan[(1 + (2*(b*c - a*d)^(1/3)*x)/(c^(1/3)*(b + a*x^3)^(1/3)))/Sqrt[3]] - 2*Log[c^(1/3) - ((b*c - a*d)^(1/3)*x)
/(b + a*x^3)^(1/3)] + Log[c^(2/3) + ((b*c - a*d)^(2/3)*x^2)/(b + a*x^3)^(2/3) + (c^(1/3)*(b*c - a*d)^(1/3)*x)/
(b + a*x^3)^(1/3)]))/(d^2*(b*c - a*d)^(1/3)) + (2*a^2*b*c*(2*Sqrt[3]*ArcTan[(1 + (2*(b*c - a*d)^(1/3)*x)/(c^(1
/3)*(b + a*x^3)^(1/3)))/Sqrt[3]] - 2*Log[c^(1/3) - ((b*c - a*d)^(1/3)*x)/(b + a*x^3)^(1/3)] + Log[c^(2/3) + ((
b*c - a*d)^(2/3)*x^2)/(b + a*x^3)^(2/3) + (c^(1/3)*(b*c - a*d)^(1/3)*x)/(b + a*x^3)^(1/3)]))/(d*(b*c - a*d)^(1
/3)))/(108*c^(8/3))

Maple [A] (verified)

Time = 4.80 (sec) , antiderivative size = 505, normalized size of antiderivative = 1.29

method	result	size
pseudoelliptic	\(\frac {\frac {9 b^{\frac {8}{3}} c^{3} \left (\frac {a d -b c}{c}\right )^{\frac {1}{3}} \left (d \,x^{3}+c \right )^{2} \ln \left (\frac {b^{\frac {2}{3}} x^{2}+b^{\frac {1}{3}} \left (b \,x^{3}+a \right )^{\frac {1}{3}} x +\left (b \,x^{3}+a \right )^{\frac {2}{3}}}{x^{2}}\right )}{2}+\left (5 a^{2} d^{2}+6 a b c d +9 b^{2} c^{2}\right ) \left (d \,x^{3}+c \right )^{2} \left (a d -b c \right ) \ln \left (\frac {\left (\frac {a d -b c}{c}\right )^{\frac {1}{3}} x +\left (b \,x^{3}+a \right )^{\frac {1}{3}}}{x}\right )-9 \sqrt {3}\, b^{\frac {8}{3}} c^{3} \left (\frac {a d -b c}{c}\right )^{\frac {1}{3}} \left (d \,x^{3}+c \right )^{2} \arctan \left (\frac {\sqrt {3}\, \left (b^{\frac {1}{3}} x +2 \left (b \,x^{3}+a \right )^{\frac {1}{3}}\right )}{3 b^{\frac {1}{3}} x}\right )-9 b^{\frac {8}{3}} c^{3} \left (\frac {a d -b c}{c}\right )^{\frac {1}{3}} \left (d \,x^{3}+c \right )^{2} \ln \left (\frac {-b^{\frac {1}{3}} x +\left (b \,x^{3}+a \right )^{\frac {1}{3}}}{x}\right )+\frac {\left (3 \left (b \,x^{3}+a \right )^{\frac {2}{3}} x d \left (5 a \,d^{2} x^{3}+9 b c d \,x^{3}+8 a c d +6 b \,c^{2}\right ) c \left (\frac {a d -b c}{c}\right )^{\frac {1}{3}}-\left (-2 \arctan \left (\frac {\sqrt {3}\, \left (\left (\frac {a d -b c}{c}\right )^{\frac {1}{3}} x -2 \left (b \,x^{3}+a \right )^{\frac {1}{3}}\right )}{3 \left (\frac {a d -b c}{c}\right )^{\frac {1}{3}} x}\right ) \sqrt {3}+\ln \left (\frac {\left (\frac {a d -b c}{c}\right )^{\frac {2}{3}} x^{2}-\left (\frac {a d -b c}{c}\right )^{\frac {1}{3}} \left (b \,x^{3}+a \right )^{\frac {1}{3}} x +\left (b \,x^{3}+a \right )^{\frac {2}{3}}}{x^{2}}\right )\right ) \left (5 a^{2} d^{2}+6 a b c d +9 b^{2} c^{2}\right ) \left (d \,x^{3}+c \right )^{2}\right ) \left (a d -b c \right )}{2}}{27 \left (\frac {a d -b c}{c}\right )^{\frac {1}{3}} \left (d \,x^{3}+c \right )^{2} d^{3} c^{3}}\)	\(505\)

[In]

int((b*x^3+a)^(8/3)/(d*x^3+c)^3,x,method=_RETURNVERBOSE)

[Out]

1/27*(9/2*b^(8/3)*c^3*((a*d-b*c)/c)^(1/3)*(d*x^3+c)^2*ln((b^(2/3)*x^2+b^(1/3)*(b*x^3+a)^(1/3)*x+(b*x^3+a)^(2/3
))/x^2)+(5*a^2*d^2+6*a*b*c*d+9*b^2*c^2)*(d*x^3+c)^2*(a*d-b*c)*ln((((a*d-b*c)/c)^(1/3)*x+(b*x^3+a)^(1/3))/x)-9*
3^(1/2)*b^(8/3)*c^3*((a*d-b*c)/c)^(1/3)*(d*x^3+c)^2*arctan(1/3*3^(1/2)*(b^(1/3)*x+2*(b*x^3+a)^(1/3))/b^(1/3)/x
)-9*b^(8/3)*c^3*((a*d-b*c)/c)^(1/3)*(d*x^3+c)^2*ln((-b^(1/3)*x+(b*x^3+a)^(1/3))/x)+1/2*(3*(b*x^3+a)^(2/3)*x*d*
(5*a*d^2*x^3+9*b*c*d*x^3+8*a*c*d+6*b*c^2)*c*((a*d-b*c)/c)^(1/3)-(-2*arctan(1/3*3^(1/2)*(((a*d-b*c)/c)^(1/3)*x-
2*(b*x^3+a)^(1/3))/((a*d-b*c)/c)^(1/3)/x)*3^(1/2)+ln((((a*d-b*c)/c)^(2/3)*x^2-((a*d-b*c)/c)^(1/3)*(b*x^3+a)^(1
/3)*x+(b*x^3+a)^(2/3))/x^2))*(5*a^2*d^2+6*a*b*c*d+9*b^2*c^2)*(d*x^3+c)^2)*(a*d-b*c))/((a*d-b*c)/c)^(1/3)/(d*x^
3+c)^2/d^3/c^3

Fricas [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 954 vs. \(2 (334) = 668\).

Time = 1.95 (sec) , antiderivative size = 954, normalized size of antiderivative = 2.44 \[ \int \frac {\left (a+b x^3\right )^{8/3}}{\left (c+d x^3\right )^3} \, dx=-\frac {2 \, \sqrt {3} {\left ({\left (9 \, b^{2} c^{2} d^{2} + 6 \, a b c d^{3} + 5 \, a^{2} d^{4}\right )} x^{6} + 9 \, b^{2} c^{4} + 6 \, a b c^{3} d + 5 \, a^{2} c^{2} d^{2} + 2 \, {\left (9 \, b^{2} c^{3} d + 6 \, a b c^{2} d^{2} + 5 \, a^{2} c d^{3}\right )} x^{3}\right )} \left (\frac {b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}}{c^{2}}\right )^{\frac {1}{3}} \arctan \left (-\frac {\sqrt {3} {\left (b c - a d\right )} x + 2 \, \sqrt {3} {\left (b x^{3} + a\right )}^{\frac {1}{3}} c \left (\frac {b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}}{c^{2}}\right )^{\frac {1}{3}}}{3 \, {\left (b c - a d\right )} x}\right ) + 18 \, \sqrt {3} {\left (b^{2} c^{2} d^{2} x^{6} + 2 \, b^{2} c^{3} d x^{3} + b^{2} c^{4}\right )} \left (-b^{2}\right )^{\frac {1}{3}} \arctan \left (-\frac {\sqrt {3} b x - 2 \, \sqrt {3} {\left (b x^{3} + a\right )}^{\frac {1}{3}} \left (-b^{2}\right )^{\frac {1}{3}}}{3 \, b x}\right ) - 2 \, {\left ({\left (9 \, b^{2} c^{2} d^{2} + 6 \, a b c d^{3} + 5 \, a^{2} d^{4}\right )} x^{6} + 9 \, b^{2} c^{4} + 6 \, a b c^{3} d + 5 \, a^{2} c^{2} d^{2} + 2 \, {\left (9 \, b^{2} c^{3} d + 6 \, a b c^{2} d^{2} + 5 \, a^{2} c d^{3}\right )} x^{3}\right )} \left (\frac {b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}}{c^{2}}\right )^{\frac {1}{3}} \log \left (\frac {c x \left (\frac {b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}}{c^{2}}\right )^{\frac {2}{3}} - {\left (b x^{3} + a\right )}^{\frac {1}{3}} {\left (b c - a d\right )}}{x}\right ) - 18 \, {\left (b^{2} c^{2} d^{2} x^{6} + 2 \, b^{2} c^{3} d x^{3} + b^{2} c^{4}\right )} \left (-b^{2}\right )^{\frac {1}{3}} \log \left (-\frac {\left (-b^{2}\right )^{\frac {2}{3}} x - {\left (b x^{3} + a\right )}^{\frac {1}{3}} b}{x}\right ) + 9 \, {\left (b^{2} c^{2} d^{2} x^{6} + 2 \, b^{2} c^{3} d x^{3} + b^{2} c^{4}\right )} \left (-b^{2}\right )^{\frac {1}{3}} \log \left (-\frac {\left (-b^{2}\right )^{\frac {1}{3}} b x^{2} - {\left (b x^{3} + a\right )}^{\frac {1}{3}} \left (-b^{2}\right )^{\frac {2}{3}} x - {\left (b x^{3} + a\right )}^{\frac {2}{3}} b}{x^{2}}\right ) + {\left ({\left (9 \, b^{2} c^{2} d^{2} + 6 \, a b c d^{3} + 5 \, a^{2} d^{4}\right )} x^{6} + 9 \, b^{2} c^{4} + 6 \, a b c^{3} d + 5 \, a^{2} c^{2} d^{2} + 2 \, {\left (9 \, b^{2} c^{3} d + 6 \, a b c^{2} d^{2} + 5 \, a^{2} c d^{3}\right )} x^{3}\right )} \left (\frac {b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}}{c^{2}}\right )^{\frac {1}{3}} \log \left (-\frac {{\left (b c - a d\right )} x^{2} \left (\frac {b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}}{c^{2}}\right )^{\frac {1}{3}} + {\left (b x^{3} + a\right )}^{\frac {1}{3}} c x \left (\frac {b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}}{c^{2}}\right )^{\frac {2}{3}} + {\left (b x^{3} + a\right )}^{\frac {2}{3}} {\left (b c - a d\right )}}{x^{2}}\right ) + 3 \, {\left ({\left (9 \, b^{2} c^{2} d^{2} - 4 \, a b c d^{3} - 5 \, a^{2} d^{4}\right )} x^{4} + 2 \, {\left (3 \, b^{2} c^{3} d + a b c^{2} d^{2} - 4 \, a^{2} c d^{3}\right )} x\right )} {\left (b x^{3} + a\right )}^{\frac {2}{3}}}{54 \, {\left (c^{2} d^{5} x^{6} + 2 \, c^{3} d^{4} x^{3} + c^{4} d^{3}\right )}} \]

[In]

integrate((b*x^3+a)^(8/3)/(d*x^3+c)^3,x, algorithm="fricas")

[Out]

-1/54*(2*sqrt(3)*((9*b^2*c^2*d^2 + 6*a*b*c*d^3 + 5*a^2*d^4)*x^6 + 9*b^2*c^4 + 6*a*b*c^3*d + 5*a^2*c^2*d^2 + 2*
(9*b^2*c^3*d + 6*a*b*c^2*d^2 + 5*a^2*c*d^3)*x^3)*((b^2*c^2 - 2*a*b*c*d + a^2*d^2)/c^2)^(1/3)*arctan(-1/3*(sqrt
(3)*(b*c - a*d)*x + 2*sqrt(3)*(b*x^3 + a)^(1/3)*c*((b^2*c^2 - 2*a*b*c*d + a^2*d^2)/c^2)^(1/3))/((b*c - a*d)*x)
) + 18*sqrt(3)*(b^2*c^2*d^2*x^6 + 2*b^2*c^3*d*x^3 + b^2*c^4)*(-b^2)^(1/3)*arctan(-1/3*(sqrt(3)*b*x - 2*sqrt(3)
*(b*x^3 + a)^(1/3)*(-b^2)^(1/3))/(b*x)) - 2*((9*b^2*c^2*d^2 + 6*a*b*c*d^3 + 5*a^2*d^4)*x^6 + 9*b^2*c^4 + 6*a*b
*c^3*d + 5*a^2*c^2*d^2 + 2*(9*b^2*c^3*d + 6*a*b*c^2*d^2 + 5*a^2*c*d^3)*x^3)*((b^2*c^2 - 2*a*b*c*d + a^2*d^2)/c
^2)^(1/3)*log((c*x*((b^2*c^2 - 2*a*b*c*d + a^2*d^2)/c^2)^(2/3) - (b*x^3 + a)^(1/3)*(b*c - a*d))/x) - 18*(b^2*c
^2*d^2*x^6 + 2*b^2*c^3*d*x^3 + b^2*c^4)*(-b^2)^(1/3)*log(-((-b^2)^(2/3)*x - (b*x^3 + a)^(1/3)*b)/x) + 9*(b^2*c
^2*d^2*x^6 + 2*b^2*c^3*d*x^3 + b^2*c^4)*(-b^2)^(1/3)*log(-((-b^2)^(1/3)*b*x^2 - (b*x^3 + a)^(1/3)*(-b^2)^(2/3)
*x - (b*x^3 + a)^(2/3)*b)/x^2) + ((9*b^2*c^2*d^2 + 6*a*b*c*d^3 + 5*a^2*d^4)*x^6 + 9*b^2*c^4 + 6*a*b*c^3*d + 5*
a^2*c^2*d^2 + 2*(9*b^2*c^3*d + 6*a*b*c^2*d^2 + 5*a^2*c*d^3)*x^3)*((b^2*c^2 - 2*a*b*c*d + a^2*d^2)/c^2)^(1/3)*l
og(-((b*c - a*d)*x^2*((b^2*c^2 - 2*a*b*c*d + a^2*d^2)/c^2)^(1/3) + (b*x^3 + a)^(1/3)*c*x*((b^2*c^2 - 2*a*b*c*d
+ a^2*d^2)/c^2)^(2/3) + (b*x^3 + a)^(2/3)*(b*c - a*d))/x^2) + 3*((9*b^2*c^2*d^2 - 4*a*b*c*d^3 - 5*a^2*d^4)*x^
4 + 2*(3*b^2*c^3*d + a*b*c^2*d^2 - 4*a^2*c*d^3)*x)*(b*x^3 + a)^(2/3))/(c^2*d^5*x^6 + 2*c^3*d^4*x^3 + c^4*d^3)

Sympy [F(-1)]

Timed out. \[ \int \frac {\left (a+b x^3\right )^{8/3}}{\left (c+d x^3\right )^3} \, dx=\text {Timed out} \]

[In]

integrate((b*x**3+a)**(8/3)/(d*x**3+c)**3,x)

[Out]

Timed out

Maxima [F]

\[ \int \frac {\left (a+b x^3\right )^{8/3}}{\left (c+d x^3\right )^3} \, dx=\int { \frac {{\left (b x^{3} + a\right )}^{\frac {8}{3}}}{{\left (d x^{3} + c\right )}^{3}} \,d x } \]

[In]

integrate((b*x^3+a)^(8/3)/(d*x^3+c)^3,x, algorithm="maxima")

[Out]

integrate((b*x^3 + a)^(8/3)/(d*x^3 + c)^3, x)

Giac [F]

\[ \int \frac {\left (a+b x^3\right )^{8/3}}{\left (c+d x^3\right )^3} \, dx=\int { \frac {{\left (b x^{3} + a\right )}^{\frac {8}{3}}}{{\left (d x^{3} + c\right )}^{3}} \,d x } \]

[In]

integrate((b*x^3+a)^(8/3)/(d*x^3+c)^3,x, algorithm="giac")

[Out]

integrate((b*x^3 + a)^(8/3)/(d*x^3 + c)^3, x)

Mupad [F(-1)]

Timed out. \[ \int \frac {\left (a+b x^3\right )^{8/3}}{\left (c+d x^3\right )^3} \, dx=\int \frac {{\left (b\,x^3+a\right )}^{8/3}}{{\left (d\,x^3+c\right )}^3} \,d x \]

[In]

int((a + b*x^3)^(8/3)/(c + d*x^3)^3,x)

[Out]

int((a + b*x^3)^(8/3)/(c + d*x^3)^3, x)